Nothing
best.match <-
function(m1, m2, perms){
## Matches the columns of row m2 to the columns of m1.
## Values should be all positive or all negative.
## Returns a list containing
## [1] the ordering of the cols of m2 that corresponds to m1
## [2] the absolute-valued difference between the matched m1 and m2
## Brute force approach
products <- t(m1)%*%(m2)
maxPerm <- -1
maxSum <- 0
for(p in 1:nrow(perms)){
s <- 0
for(i in 1:nrow(products)){
s <- s+products[i,perms[p,i]]
}
if(s > maxSum){
maxSum <- s
maxPerm <- p
}
}
if(maxPerm == -1){
warning("best_match failed!")
}
return(list(perms[maxPerm,], sum(abs(m1 - m2[,perms[maxPerm,]]))))
}
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