Nothing
"localMaximum" <-
function (x, winSize = 5) {
len <- length(x)
rNum <- ceiling(len/winSize)
## Transform the vector as a matrix with column length equals winSize
## and find the maximum position at each row.
y <- matrix(c(x, rep(x[len], rNum * winSize - len)), nrow=winSize)
y.maxInd <- apply(y, 2, which.max)
## Only keep the maximum value larger than the boundary values
selInd <- which(apply(y, 2, function(x) max(x) > x[1] & max(x) > x[winSize]))
## keep the result
localMax <- rep(0, len)
localMax[(selInd-1) * winSize + y.maxInd[selInd]] <- 1
## Shift the vector with winSize/2 and do the same operation
shift <- floor(winSize/2)
rNum <- ceiling((len + shift)/winSize)
y <- matrix(c(rep(x[1], shift), x, rep(x[len], rNum * winSize - len - shift)), nrow=winSize)
y.maxInd <- apply(y, 2, which.max)
## Only keep the maximum value larger than the boundary values
selInd <- which(apply(y, 2, function(x) max(x) > x[1] & max(x) > x[winSize]))
localMax[(selInd-1) * winSize + y.maxInd[selInd] - shift] <- 1
## Check whether there is some local maxima have in between distance less than winSize
maxInd <- which(localMax > 0)
selInd <- which(diff(maxInd) < winSize)
if (length(selInd) > 0) {
selMaxInd1 <- maxInd[selInd]
selMaxInd2 <- maxInd[selInd + 1]
temp <- x[selMaxInd1] - x[selMaxInd2]
localMax[selMaxInd1[temp <= 0]] <- 0
localMax[selMaxInd2[temp > 0]] <- 0
}
return(localMax)
}
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